US basketball

Bucks’ Jrue Holiday wins NBA Sportsmanship Award

Reuters
Bucks’ Jrue Holiday wins NBA Sportsmanship Award

TOP PICK. Jrue Holiday earns 130 of the 343 first-place votes for the NBA Sportsmanship Award.

Milwaukee Bucks' Instagram page

Bucks guard Jrue Holiday beats Celtics' Kemba Walker and Heat's Bam Adebayo for the award given to the player that best represents the ideals of sportsmanship on the court

Milwaukee Bucks guard Jrue Holiday received the Joe Dumars Trophy on Friday, June 4 as the winner of the 2020-21 NBA Sportsmanship Award.

The annual award is presented to the player who best represents the ideals of sportsmanship on the court, with each of the league’s 30 teams nominating one of its own players.

Holiday received 130 of 343 first-place votes and earned 2,752 points in voting by NBA players. Boston’s Kemba Walker, a two-time winner of the award, finished second with 2,474 points and Miami’s Bam Adebayo placed third with 2,199.

Sacramento’s Harrison Barnes (2,008), San Antonio’s Derrick White (1,635) and Minnesota’s Josh Okogie (1,280) were also finalists for the award.

The six finalists were awarded 11 points for each first-place vote, 9 for each second-place vote, 7 for each third-place vote, 5 for each fourth-place vote, 3 for each fifth-place vote, and 1 point for each sixth-place vote.

Holiday, 30, averaged 17.7 points, 6.1 assists, and 4.5 rebounds in 59 games (56 starts) during his first season with the Bucks and 12th season in the NBA.

A first-round pick by Philadelphia (17th overall) in 2009, Holiday has career averages of 16.0 points, 6.4 assists, and 4.0 rebounds in 772 games (696 starts) with the 76ers (2009-13), New Orleans Pelicans (2013-20), and Bucks.

The award is named for Dumars, a Hall of Fame guard for the Detroit Pistons who was the inaugural Sportsmanship Award recipient in the 1995-96 season. – Rappler.com